STANDARD Physics Simple Harmonic Motion MCQ Question
A simple pendulum made of a bob of mass m and a metallic wire of negligible mass has time period 2s at T = 0°C. If the temperature of the wire is increased and the corresponding change in its time period is plotted against its temperature, the resulting graph is a line of slope S. If the coefficient of linear expansion of metal is α, then the value of S is
1/α
2α
α
α/2
Correct Answer
Detailed Explanation
The variation of length of the wire with temperature is given by l = αlΔθ. The time period of a simple pendulum is T₀ = 2π√(l/g). The change in time period ΔT = T₀ - T₀ = αT₀/2. Therefore, the slope S = α.
Found an issue with this question?
Related Questions
More from
Assertion (A): The acceleration in simple harmonic motion is always directed towards the mean position. | Reason (R): In simple harmonic motion, accel...
What is the relationship between the driving frequency and the amplitude of an oscillator in Simple Harmonic Motion?
What happens to the mechanical energy of a damped oscillator during its motion?