STANDARD Physics Simple Harmonic Motion MCQ Question
A body of mass 5 kg is executing simple harmonic motion with amplitude 5 m and frequency ω = rad/sec when it is 1 m away from mean position, what will be the kinetic energy and potential energy acquired by the body?
15000 J, 562.5 J
1562.5 J, 65.5 J
1500 J, 156.2 J
1500 J, 62.5 J
Correct Answer
Detailed Explanation
The kinetic energy (KE) is calculated using KE = 1/2 mω²(a² - y²). Substituting the values, KE = 1500 J. The potential energy (PE) is calculated using PE = 1/2 mω²y², which gives PE = 62.5 J.
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