STANDARD Physics Refraction MCQ Question
Three immiscible liquids of densities d₁ > d₂ > d₃ and refractive indices μ₁ > μ₂ > μ₃ are put in a beaker. The height of each liquid column is h/3. A dot is made at the bottom of the beaker. For near normal vision, the apparent depth of the dot is
h/6 (1/μ₁ + 1/μ₂ + 1/μ₃)
h/6 (1/μ₁ - 1/μ₂ - 1/μ₃)
h/3 (1/μ₁ - 1/μ₂ - 1/μ₃)
h/3 (1/μ₁ + 1/μ₂ + 1/μ₃)
Correct Answer
Detailed Explanation
The apparent depth is calculated by summing the contributions of each layer's refractive index. The formula used is h/3 (1/μ₁ + 1/μ₂ + 1/μ₃), which accounts for the refractive indices of all three layers.
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