STANDARD Physics Prism MCQ Question
The angle of minimum deviation for prism of angle π/3 is π/6, if the velocity of light in vacuum is 3 × 10⁸ m s⁻¹, then the velocity of light in material of the prism is
2.12 × 10⁸ m s⁻¹
1.12 × 10⁸ m s⁻¹
4.12 × 10⁸ m s⁻¹
5.12 × 10⁸ m s⁻¹
Correct Answer
Detailed Explanation
Using the formula μ = sin((A + δₘ)/2) / sin(A/2), and given values, we find μ = 1.414. The velocity of light in the material is v = c/μ = 2.12 × 10⁸ m s⁻¹.
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