STANDARD Physics Nuclear Fission MCQ Question
A nuclear fission is given below A₂₄₀ → B₁₀₀ + C₁₄₀ + Q(energy) Let binding energy per nucleon of nucleus A, B and C is 7.6 MeV, 8.1 MeV and 8.1 MeV respectively. Value of Q is :- (Approximately)
20 MeV
220 MeV
120 MeV
240 MeV
Correct Answer
Detailed Explanation
Q = Related every = nBEB + nCEC − nAEA. Q = 1 × 8.1 MeV + 140 × 8.1 MeV − 240 × 7.6 MeV. Q = 1944 MeV − 1824 MeV = 120 MeV.
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