STANDARD Physics Fusion Reactions MCQ Question
The binding energy per nucleon of deuterium and helium nuclei are 1.1 MeV and 7.0 MeV respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is
23.6 MeV
2.2 MeV
28.0 MeV
30.2 MeV
Correct Answer
Detailed Explanation
The binding energy per nucleon of a deuterium = 1.1 MeV. Total binding energy = 2 × 1.1 = 2.2 MeV. The binding energy per nucleon of a helium nuclei = 7 MeV. Total binding energy = 4 × 7 = 28 MeV. Hence, energy released E = (28 – 2 × 2.2) = 23.6 MeV.
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