STANDARDPhysics-Nuclear Physics
STANDARD Physics Binding Energy MCQ Question
Type: MCQ-numerical-Medium
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of ⁴₂He, if mass of ⁴₂He = 4.0015 u is
A
0.0305 erg
B
0.0305 J
C
28.4 MeV
D
0.061 u
Correct Answer
Option C
Detailed Explanation
The binding energy is calculated using the mass defect, which is the difference between the mass of the nucleons and the actual mass of the nucleus. The mass defect is 0.0305 u, and the binding energy is 0.0305 × 931 MeV = 28.4 MeV.
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