STANDARD Physics Projectile Motion MCQ Question
An aeroplane flying horizontally with a speed of 360 km h⁻¹ releases a bomb at a height of 490 m from the ground. If g = 9.8 m s⁻², it will strike the ground at
10 km
100 km
1 km
16 km
Correct Answer
Detailed Explanation
The time taken by the bomb to fall through a height of 490 m is calculated using the formula t = √(2h/g) = √(2×490/9.8) = 10 s. The horizontal distance covered is then velocity × time = 360 km h⁻¹ × 10 s = 1 km.
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