STANDARD Physics Equilibrium of Forces MCQ Question
A block of mass 5 kg is suspended by a massless rope of length 2 m from the ceiling. A force of 50 N is applied in the horizontal direction at the midpoint P of the rope, as shown in the figure. The angle made by the rope with the vertical in equilibrium is (Take g = 10 m s⁻²)
30°
40°
60°
45°
Correct Answer
Detailed Explanation
In equilibrium, the vertical component of tension balances the weight, and the horizontal component balances the applied force. Using trigonometry, tan θ = horizontal force / weight = 50 / (5 × 10) = 1. Therefore, θ = 45°.
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