STANDARD Physics Stress and Strain MCQ Question
A light rod of length 2 m is suspended from the ceiling horizontally by means of two vertical wires of equal length tied to its ends. One of the wires is made of steel and is of cross-section 0.1 cm² and the other of brass off cross-section 0.2 cm². Along the rod at what distance a weight may be hung to produce equal stresses in both the wires? (Yₛₜₑₑₗ = 2 × 10¹¹ N m⁻², Y₆ᵣₐₛₛ = 1 × 10¹¹ N m⁻²)
4/3 m from steel wire
4/3 m from brass wire
1 m from steel wire
1/4 m from brass wire
Correct Answer
Detailed Explanation
For equal stress in both the wires, Tₛ/Aₛ = T₆/A₆. Using the given cross-sectional areas and Young's moduli, the distance x from the steel wire is calculated as 4/3 m.
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