STANDARD Physics Shear Modulus MCQ Question
Two parallel and opposite forces each 5000 N are applied tangentially to the upper and lower faces of a cubical metal block off side 25 cm. The angle of shear is (The shear modulus of the metal is 80 GPa.)
10⁻⁴ rad
10⁻⁵ rad
10⁻⁶ rad
10⁻⁷ rad
Correct Answer
Detailed Explanation
The angle of shear θ is calculated using the formula θ = F / (Aη), where F is the force, A is the area, and η is the shear modulus. Substituting the given values, θ = 5000 / (625 × 10⁻⁴ × 80 × 10⁹) = 10⁻⁶ rad.
Found an issue with this question?
Related Questions
More from
Which combination of statements is correct regarding stress and strain in solids?
Match Column-I with Column-II. Column-I Column-II (a) Young's Modulus (i) 300 × 10^6 N m –2 (b) Yield strength of steel (ii) 9.4 × 10^9 ...
Match Column-I with Column-II. Column-I Column-II (a) Young's Modulus (i) Restoring force per unit area (b) Stress (ii) Rati...