STANDARDPhysics-Properties of Solids
STANDARD Physics Shear Modulus MCQ Question
Type: MCQ-numerical-Medium-Class 11
Two parallel and opposite forces each 5000 N are applied tangentially to the upper and lower faces of a cubical metal block off side 25 cm. The angle of shear is (The shear modulus of the metal is 80 GPa.)
A
10⁻⁴ rad
B
10⁻⁵ rad
C
10⁻⁶ rad
D
10⁻⁷ rad
Correct Answer
Option C
Detailed Explanation
The angle of shear θ is calculated using the formula θ = F / (Aη), where F is the force, A is the area, and η is the shear modulus. Substituting the given values, θ = 5000 / (625 × 10⁻⁴ × 80 × 10⁹) = 10⁻⁶ rad.
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