STANDARD Physics Elasticity MCQ Question
A 15 kg mass fastened to the end of a steel wire of unstretched length 1.0 m is whirled in a vertical circle with an angular velocity of 2 rev s⁻¹ at the bottom of the circle. The cross-section of the wire is 0.05 cm². The elongation of the wire when the mass is at the lowest point of its path is (Take, g = 10 m s⁻², Yₛₜₑₑₗ = 2 × 10¹¹ N m⁻²)
0.52 mm
1.52 mm
2.52 mm
3.52 mm
Correct Answer
Detailed Explanation
The stretching force at the lowest point is calculated using F = mg + mrω². Substituting the given values, F = 2516 N. Using Young's modulus, ΔL = FL/AY, the elongation ΔL is found to be 2.52 mm.
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