STANDARD Physics Torque on a Magnetic Dipole MCQ Question
If a solenoid is having magnetic moment of 0.65 J T⁻¹ is free to turn about the vertical direction and has a uniform horizontal magnetic field of 0.25T applied. What is the magnitude of the torque on the solenoid when its axis makes an angle of 30° with the direction of applied field?
0.075 N m
0.080 N m
0.081 N m
0.091 N m
Correct Answer
Detailed Explanation
The torque τ on a magnetic dipole in a magnetic field is given by τ = MB sin θ. Here, M = 0.65 J T⁻¹, B = 0.25 T, and θ = 30°. Therefore, τ = 0.65 × 0.25 × sin 30° = 0.081 N m.
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