STANDARDPhysics-Magnetism
STANDARD Physics Magnetic Torque MCQ Question
Type: MCQ-conceptual-Medium
A bar magnet has a magnetic moment of 200 A m². The magnet is suspended in a magnetic field of 0.30 N A⁻¹ m⁻¹. The torque required to rotate the magnet from its equilibrium position through an angle of 30°, will be
A
30 N m
B
30√3 N m
C
60 N m
D
60√3 N m
Correct Answer
Option A
Detailed Explanation
Torque experienced by a magnet in a magnetic field is given by τ = MB sin θ. Here, M = 200 A m², B = 0.30 N A⁻¹ m⁻¹, and θ = 30°. Therefore, τ = 200 × 0.30 × sin 30° = 30 N m.
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