STANDARD Physics Magnetic Torque and Moment MCQ Question
A bar magnet of magnetic moment M and moment of inertia I is freely suspended such that the magnetic axial line is in the direction of magnetic meridian. If the magnet is displaced by a very small angle θ, angular acceleration is (magnetic induction of earth's horizontal field is Bₕ)
MθBₕ/I
IBₕθ/M
Mθ/IBₕ
Iθ/MBₕ
Correct Answer
Detailed Explanation
Restoring torque on the magnet, τ = -2mBₕsinθ ≈ -MBₕθ. If θ is small, sin θ ≈ θ, leading to α = MBₕθ/I. Thus, the angular acceleration α = MθBₕ/I.
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