STANDARD Physics Magnetic Field MCQ Question
A short bar magnet has a magnetic moment of 0.48 J T⁻¹. The magnitude and direction of magnetic field produced by the magnet at a distance of 10 cm from the centre of the magnet on its axis is
0.48 × 10⁻⁴ T along N-S direction
0.28 × 10⁻⁴ T along S-N direction
0.28 × 10⁻⁴ T along N-S direction
0.96 × 10⁻⁴ T along S-N direction
Correct Answer
Detailed Explanation
On the axis of the magnet, B = μ₀ / 4π × 2M / d³. Substituting the values, B = 10⁻⁷ × 2 × 0.48 / (0.1)³ = 0.96 × 10⁻⁴ T, along S-N direction.
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