STANDARDPhysics-Magnetism
STANDARD Physics Magnetic Field due to Current MCQ Question
Type: MCQ-numerical-Medium
A circular loop of radius 3 cm is having a current of 12.5 A. The magnitude of magnetic field at a distance of 4 cm on its axis is
A
5.65 × 10⁻⁵ T
B
5.27 × 10⁻⁵ T
C
6.54 × 10⁻⁵ T
D
9.20 × 10⁻⁵ T
Correct Answer
Option A
Detailed Explanation
The magnetic field at a point on the axis of a circular loop is given by B = (μ₀IR²) / (2(R² + x²)^(3/2)). Substituting the given values, we find B = 5.65 × 10⁻⁵ T.
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