STANDARDPhysics-Magnetism

STANDARD Physics Magnetic Field due to Current MCQ Question

Type: MCQ-conceptual-Medium

A current I is flowing through a loop. The direction of the current and the shape of the loop are as shown in the figure. The magnetic field at the centre of the loop is μ0IR\frac{\mu_0 I}{R} time (Here, MA = R, MB = 2R, ∠DMA = 90°)

Question diagram
A

516\frac{5}{16}, out of the plane of the paper.

B

516\frac{5}{16}, into the plane of the paper.

C

716\frac{7}{16}, out of the plane of the paper.

D

716\frac{7}{16}, into the plane of the paper.

Correct Answer

Option D

Detailed Explanation

The magnetic field at the centre M due to the current through the curved portion DA is B1=μ0I4πR×3π2B_1 = \frac{\mu_0 I}{4 \pi R} \times \frac{3\pi}{2} into the plane of the paper. The magnetic field due to the straight portion AB is zero. Therefore, the net magnetic field is 716\frac{7}{16} into the plane of the paper.

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