STANDARD Physics Magnetic Dipole MCQ Question
The magnetic moment of a short bar magnet placed with its magnetic axis at 30° to an external field of 900 G and experiences a torque of 0.02 N m is
0.35 A m²
0.44 A m²
2.45 A m²
1.5 A m²
Correct Answer
Detailed Explanation
The torque τ on a magnetic dipole in a magnetic field is given by τ = MB sin θ. Here, B = 900 G = 9 × 10⁻² T, τ = 0.02 N m, and θ = 30°. Solving for M, M = τ / (B sin θ) = 0.02 / (9 × 10⁻² × 0.5) = 0.44 A m².
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