STANDARDPhysics-Magnetism

STANDARD Physics Magnetic Dipole in a Uniform Magnetic Field MCQ Question

Type: MCQ-numerical-Medium

A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10⁻² J. What is the magnitude of magnetic moment of the magnet?

A

0.36 J T⁻¹

B

0.38 J T⁻¹

C

0.36 J T⁻²

D

0.38 J T⁻²

Correct Answer

Option A

Detailed Explanation

The torque τ experienced by a magnetic dipole in a magnetic field is given by τ = MB sin θ. Given τ = 4.5 × 10⁻² J, B = 0.25 T, and θ = 30°, we can solve for M: M = τ / (B sin θ) = 4.5 × 10⁻² / (0.25 × 0.5) = 0.36 J T⁻¹.

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