STANDARD Physics Magnetic Dipole in a Uniform Magnetic Field MCQ Question
A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.25 T experiences a torque of magnitude equal to 4.5 × 10⁻² J. What is the magnitude of magnetic moment of the magnet?
0.36 J T⁻¹
0.38 J T⁻¹
0.36 J T⁻²
0.38 J T⁻²
Correct Answer
Detailed Explanation
The torque τ experienced by a magnetic dipole in a magnetic field is given by τ = MB sin θ. Given τ = 4.5 × 10⁻² J, B = 0.25 T, and θ = 30°, we can solve for M: M = τ / (B sin θ) = 4.5 × 10⁻² / (0.25 × 0.5) = 0.36 J T⁻¹.
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