STANDARDPhysics-Magnetism
STANDARD Physics Magnetic Dipole in a Field MCQ Question
Type: MCQ-conceptual-Medium
A circular current loop of magnetic moment M is in an arbitrary orientation in an external magnetic field B. The work done to rotate the loop by 30° about an axis perpendicular to its plane is
A
MB
B
√3MB/2
C
MB/2
D
zero
Correct Answer
Option D
Detailed Explanation
The work done in rotating a magnetic dipole in a uniform magnetic field is given by W = MB(cosθ₁ - cosθ₂). For a 30° rotation, θ₁ = θ₂, so W = 0.
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