STANDARDPhysics-Magnetic Effects of Current
STANDARD Physics Motion of Charged Particles in Magnetic Field MCQ Question
Type: MCQ-conceptual-Medium
A charged particle is moving on circular path with velocity v in a uniform magnetic field B, if the velocity of the charged particle is doubled and strength of magnetic field is halved, then radius becomes
A
8 times
B
4 times
C
2 times
D
16 times
Correct Answer
Option B
Detailed Explanation
The radius r of the path is given by r = mv / (Bq). If v is doubled and B is halved, r becomes 2v / (0.5Bq) = 4 times the original radius.
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