STANDARD Physics Force on a Current-Carrying Conductor MCQ Question
A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is
30°
45°
60°
90°
Correct Answer
Detailed Explanation
Using F = IBl sin θ, we have sin θ = F / (IBl) = 15 / (10 × 1.5 × 2) = 1/2. Therefore, θ = 30°.
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