STANDARD Physics Normal Force MCQ Question
A person of mass 50 kg stands on a weighing scale on a lift. If the lift is ascending upwards with a uniform acceleration of 9 m s⁻², what would be the reading of the weighing scale? (Take g = 10 m s⁻²)
50 kg
60 kg
95 kg
100 kg
Correct Answer
Detailed Explanation
The reading on the scale is a measure of the force on the floor by the person. By Newton's third law, this is equal and opposite to the normal force N on the person by the floor. When the lift is ascending upwards with an acceleration of 9 m s⁻², then N = 50 × 10 + 50 × 9 = 50(10 + 9) = 950 N. The reading of the weighing machine is 95 kg.
Found an issue with this question?
Related Questions
More from Laws of Motion
More from
A force of 600 N is applied to a 10 kg block on a horizontal surface with no friction. What is the acceleration of the block?
Match Column-I with Column-II. Column-I Column-II (a) Impulse imparted to a ball by a batsman (i) Change in momentum of the ball (b) Newton's...
A block of mass 5 kg is placed on a horizontal table and experiences a static friction force of 15 N. What is the minimum force required to start movi...