STANDARD Physics Force and Motion MCQ Question
A bullet of mass 40 g moving with a speed of 90 m s⁻¹ enters a heavy wooden block and is stopped after a distance of 60 cm. The average resistive force exerted by the block on the bullet is
180 N
220 N
270 N
320 N
Correct Answer
Detailed Explanation
Using the equation v² = u² - 2as, where u = 90 m s⁻¹, v = 0, and s = 0.6 m, we find the acceleration a = -6750 m s⁻². The force is F = ma = (0.04 kg)(6750 m s⁻²) = 270 N. The negative sign indicates retardation.
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