STANDARDPhysics-Laws of Motion

STANDARD Physics Dynamics of a System of Particles MCQ Question

Type: MCQ-conceptual-Medium-Class 11

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and θ for the block to remain stationary on the wedge is

Question diagram
A

a = gcosecθ\frac{g}{\text{cosec} θ}

B

a = gsinθ\frac{g}{\text{sin} θ}

C

a=gcosθa = g \cos θ

D

a=gtanθa = g \tan θ

Correct Answer

Option D

Detailed Explanation

In a non-inertial frame, the forces acting on the block include the normal force and the pseudo force due to acceleration. By resolving forces parallel and perpendicular to the incline, we get Nsinθ = ma and Ncosθ = mg. Dividing these equations gives tanθ = a/g, leading to a = g tanθ.

Found an issue with this question?