STANDARD Physics Conservation of Momentum MCQ Question
A 100 kg gun fires a ball of 1 kg horizontally from a cliff of height 500 m. It falls on the ground at a distance of 400 m from the bottom of the cliff. The recoil velocity of the gun is (Take g = 10 m s⁻²)
0.2 m s⁻¹
0.4 m s⁻¹
0.6 m s⁻¹
0.8 m s⁻¹
Correct Answer
Detailed Explanation
The time taken by the ball to reach the ground is calculated using the formula t = √(2h/g), which gives 10 seconds. The horizontal distance covered is 400 m, so the velocity of the ball is 40 m s⁻¹. Using the conservation of linear momentum, 0 = Mv + mu, we find the recoil velocity of the gun to be -0.4 m s⁻¹. The negative sign indicates the direction is opposite to that of the ball.
Found an issue with this question?
Related Questions
More from Laws of Motion
More from
A force of 600 N is applied to a 10 kg block on a horizontal surface with no friction. What is the acceleration of the block?
Match Column-I with Column-II. Column-I Column-II (a) Impulse imparted to a ball by a batsman (i) Change in momentum of the ball (b) Newton's...
A block of mass 5 kg is placed on a horizontal table and experiences a static friction force of 15 N. What is the minimum force required to start movi...