STANDARDPhysics-Kinematics
STANDARD Physics Velocity and Acceleration MCQ Question
Type: MCQ-numerical-Medium
The velocity of the particle at any time t is given by v = 2t(3 − t) m s⁻¹. At what time is its velocity maximum?
A
2s
B
3s
C
2/3 s
D
3/2 s
Correct Answer
Option D
Detailed Explanation
Given v = 2t(3-t) or v = 6t − 2t². The derivative dv/dt = 6 − 4t. For maximum velocity, set dv/dt = 0, which gives t = 3/2 s.
Found an issue with this question?
Related Questions
More from Kinematics
A body starts from rest with an acceleration a₁, after two seconds another body B starts from rest with an acceleration a₂. If they travel equal dista...
2019Physics
A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. ...
2020Physics
Assertion: When a body is dropped or thrown upward from the same height, it would reach the ground at the same time. Reason: Direction of projection d...
2019Physics