STANDARD Physics Equations of Motion MCQ Question
The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time ‘t’ (in sec) by t = √x + 3. The displacement off the particle when its velocity is zero, will be
4 m
0 m
6 m
2 m
Correct Answer
Detailed Explanation
Given t = √x + 3, or √x = t - 3. Squaring both sides, x = (t - 3)². The velocity v = dx/dt = 2(t - 3). The velocity becomes zero when 2(t - 3) = 0, or t = 3 s. At t = 3 s, x = (3 - 3)² = 0 m.
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