STANDARD Physics Equations of Motion MCQ Question
If x = 5t + 3t² and y = 4t are the x and y co-ordinates of a particle at any time t second where x and y are in metre, then the acceleration of the particle
is zero throughout its motion
is a constant throughout its motion
depends only on its y component
varies along both x and y direction
Correct Answer
Detailed Explanation
The acceleration is the second derivative of the position with respect to time. For x = 5t + 3t², the acceleration is constant (6 m/s²) as it is the second derivative of 3t². For y = 4t, the acceleration is zero. Thus, the acceleration is constant throughout its motion.
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