STANDARD Physics Equations of Motion MCQ Question
If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1 s and 2 s is
3/2 A + 7/3 B
A/2 + B/3
3/2 A + 4B
3A + 7B
Correct Answer
Detailed Explanation
The velocity of the particle is v = At + Bt². Integrating with respect to time, we find the displacement s(t) = ∫(At + Bt²) dt = At²/2 + Bt³/3 + C. Calculating the displacement at t = 1 s and t = 2 s, the required distance is s(2) - s(1) = (2A + 8/3 B) - (A/2 + B/3) = 3/2 A + 7/3 B.
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