STANDARD Physics Acceleration MCQ Question
The x and y coordinates of the particle at any time are X = 5t − 2t² and y = 10t respectively, where x and y are in metres and t in seconds. The acceleration of the particle at t = 2 s is :
5 m s⁻²
−4 m s⁻²
−8 m s⁻²
0
Correct Answer
Detailed Explanation
The acceleration is the second derivative of the position. For x, aₓ = d²x/dt² = -4 m/s². For y, a_y = d²y/dt² = 0. Thus, the acceleration at t = 2 s is -4 m/s².
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