STANDARD Physics Bernoulli's Principle MCQ Question
In a wind tunnel experiment the pressures on the upper and lower surfaces of the wings are 0.90 × 10⁵ Pa and 0.91 × 10⁵ Pa respectively. If the area of the wing is 40 m² the net lifting force on the wing is
2 × 10⁴ N
4 × 10⁴ N
6 × 10⁴ N
8 × 10⁴ N
Correct Answer
Detailed Explanation
Pressure difference which provides the lift = Pressure difference × Area of the wing = (P₂ - P₁) × A = (0.91 × 10⁵ - 0.90 × 10⁵) Pa × 40 m² = 0.01 × 10⁵ Pa × 40 m² = 4 × 10⁴ N
Found an issue with this question?
Related Questions
More from Fluid Mechanics
Two rain drops of same radii 'r', falling with terminal velocity 'v' merge and form a bigger drop of radius R. The terminal velocity of the bigger dro...
By sucking through a straw, a student can reduce the pressure in his lungs to 750 mm of Hg (density = 13.6 g/cm³). Using the straw, he can drink water...
A submarine is designed to withstand an absolute pressure of 100 atm. How deep can it go below the water surface? (Consider the density of water = 100...