STANDARDPhysics-Fluid Mechanics
STANDARD Physics Bernoulli's Principle MCQ Question
Type: MCQ-conceptual-Easy
In the figure shown an ideal liquid is flowing through the tube which is of uniform area of cross-section. The liquid has velocities vₐ and vB, and pressures Pₐ and PB at points A and B respectively. Then
A
vB > vₐ
B
vB = vₐ
C
PB < Pₐ
D
PB = Pₐ
Correct Answer
Option B
Detailed Explanation
For a streamline flow of an ideal liquid, the velocity remains constant across points in a tube of uniform cross-section, hence vₐ = vB.
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