STANDARDPhysics-Electrostatics
STANDARD Physics Capacitors MCQ Question
Type: MCQ-conceptual-Medium
A capacitor of 2 μF is charged as shown in the diagram. When the switch S is turned to position 2, the percentage of its stored energy dissipated is
A
75%
B
80%
C
0%
D
20%
Correct Answer
Option B
Detailed Explanation
Initially, the energy stored in the 2 μF capacitor is U₁ = 1/2 CV². When the switch is turned to position 2, the charge redistributes between the capacitors, leading to a new energy U₂. The percentage loss of energy is calculated as ((U₁ - U₂) / U₁) × 100%, which results in 80%.
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