STANDARD Physics Capacitance MCQ Question
A parallel plate capacitor is made of two dielectric blocks in series. One of the blocks has thickness d₁ and dielectric constant K₁ and the other has thickness d₂ and dielectric constant K₂ as shown in figure. This arrangement can be thought as a dielectric slab of thickness d(d₁ + d₂) and effective dielectric constant K. The K is
K₁K₂{d₁ + d₂} / {K₁d₂ + K₂d₁}
K₁d₁ + K₂d₂ / d₁ + d₂
K₁d₁ + K₂d₂ / K₁ + K₂
2K₁K₂ / K₁ + K₂
Correct Answer
Detailed Explanation
The effective dielectric constant K for capacitors in series is derived from the formula for equivalent capacitance. By considering the capacitors as series, the effective K is given by K₁K₂(d₁ + d₂) / (K₁d₂ + K₂d₁).
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