STANDARDPhysics-Electrostatics
STANDARD Physics Capacitance MCQ Question
Type: MCQ-numerical-Medium
In the previous question, the rate of change of potential difference between the plates is
A
2.41 × 10⁹ V s⁻¹
B
1.87 × 10⁹ V s⁻¹
C
3.2 × 10⁻⁴ V s⁻¹
D
4.5 × 10⁻⁴ V s⁻¹
Correct Answer
Option B
Detailed Explanation
The rate of change of potential difference is given by dV/dt = I/C. Here, C = 80 × 10⁻¹² F and I = 0.15 A. Therefore, dV/dt = 0.15 / (80 × 10⁻¹²) = 1.87 × 10⁹ V s⁻¹.
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