STANDARD Physics Capacitance MCQ Question
A parallel plate capacitor is charged and then isolated. The effect of increasing the plate separation on charge, potential, capacitance respectively are
constant, decreases, decreases
increases, decreases, decreases
constant, decreases, increases
constant, increases, decreases
Correct Answer
Detailed Explanation
As the capacitor is isolated after charging, charge on it remains constant. Plate separation d increases, capacitance decreases as C = ε₀A/d and hence, potential increases as V = q/C.
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