STANDARDPhysics-Electromagnetism
STANDARD Physics Magnetic Field in Solenoids MCQ Question
Type: MCQ-numerical-Medium-Class 12
A solenoid of length 50 cm, having 100 turns carries a current of 2.5 A. The magnetic field at one end of the solenoid is
A
3.14 × 10⁻⁴ T
B
6.28 × 10⁻⁴ T
C
1.57 × 10⁻⁴ T
D
9.42 × 10⁻⁴ T
Correct Answer
Option A
Detailed Explanation
The number of turns per meter n = 100/0.5 = 200 turns/m. Using the formula B = μ₀nI/2 for the field at the end of a solenoid, we get B = (4π × 10⁻⁷ × 200 × 2.5)/2 = 3.14 × 10⁻⁴ T.
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