STANDARDPhysics-Electromagnetism

STANDARD Physics Magnetic Field in Solenoids MCQ Question

Type: MCQ-numerical-Medium-Class 12

A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns. If it carries a current of 4 A, then the magnitude of the magnetic field inside the solenoid is

A

6.024 × 10⁻³ T

B

8.024 × 10⁻³ T

C

5.024 × 10⁻³ T

D

7.024 × 10⁻³ T

Correct Answer

Option C

Detailed Explanation

The number of turns per meter n = 600/0.6 = 1000 turns/m. Using the formula B = μ₀nI, where μ₀ = 4π × 10⁻⁷ T·m/A, we get B = 4π × 10⁻⁷ × 1000 × 4 = 5.024 × 10⁻³ T.

Found an issue with this question?