STANDARDPhysics-Electromagnetic Induction
STANDARD Physics Self Inductance MCQ Question
Type: MCQ-numerical-Medium-Class 12
In a coil current falls from 5 A to 0 A in 0.2 s. If an average emf of 150 V is induced, then the self inductance of the coil is
A
4 H
B
2 H
C
3 H
D
6 H
Correct Answer
Option D
Detailed Explanation
The self inductance L can be calculated using the formula ε = -L (di/dt). Given ε = 150 V, di = 5 A, and dt = 0.2 s, we find L = ε / (di/dt) = 150 / 25 = 6 H.
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