STANDARDPhysics-Electromagnetic Induction
STANDARD Physics Self Inductance MCQ Question
Type: MCQ-numerical-Medium-Class 12
By a change of current from 5 A to 10 A in 0.1s, the self induced emf is 10 V. The change in the energy of the magnetic field of a coil will be
A
5 J
B
6 J
C
7.5 J
D
9 J
Correct Answer
Option C
Detailed Explanation
The magnetic field energies for currents I₁ and I₂ are U₁ = 1/2 L I₁² and U₂ = 1/2 L I₂². Change in energy, ΔU = U₂ - U₁ = 1/2 L (I₂² - I₁²) = 0.2 (10² - 5²) = 7.5 J.
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