STANDARD Physics Young's Modulus MCQ Question
A steel wire of length 4.5 m and cross-sectional area 3 × 10⁻⁵ m² stretches by the same amount as a copper wire of length 3.5 m and cross-sectional area of 4 × 10⁻⁵ m² under a given load. The ratio of the Young’s modulus of steel to that of copper is
1.3
1.5
1.7
1.9
Correct Answer
Detailed Explanation
For both wires, the force and extension are the same, so we use the formula for Young's modulus: Y = (F/A) / (ΔL/L). By equating the expressions for both wires and solving for the ratio, we find Yₛ/Yc = (Lₛ/Aₛ) / (Lc/Ac) = (4.5/3) / (3.5/4) = 1.7.
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