STANDARDPhysics-Elasticity
STANDARD Physics Extension due to self-weight MCQ Question
Type: MCQ-numerical-Medium
A wire of length L has a linear mass density μ, area of cross-section A and Young’s modulus Y. It is suspended vertically from a rigid support. The extension produced in the wire due to its own weight is
A
μgL²/YA
B
μgL²/2YA
C
2μgL²/YA
D
2μgL²/3YA
Correct Answer
Option B
Detailed Explanation
The extension produced in the wire due to its own weight can be calculated by considering a small element of length dx at a distance x from the free end of the wire. The tension in the wire at distance x is μgx. Integrating this over the length of the wire gives the total extension as μgL²/2YA.
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