STANDARDPhysics-Elasticity
STANDARD Physics Extension due to additional load MCQ Question
Type: MCQ-numerical-Medium
In the previous question, if the mass M is hung at the free end of the wire, then the extension produced in the wire is
A
μgL² + MgL/2YA
B
2μgL² + MgL/2YA
C
μgL² + 2MgL/2YA
D
μgL² + MgL/YA
Correct Answer
Option C
Detailed Explanation
When a mass M is hung at the free end of the wire, the tension in the wire at a distance x from the lower end is μgx + Mg. Integrating this over the length of the wire gives the total extension as (μgL² + 2MgL)/2YA.
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