STANDARD Physics Ohm's Law MCQ Question
A 7 V battery with internal resistance 2 Ω and a 3 V battery with internal resistance 1 Ω are connected to a 10 Ω resistor as shown in figure, the current in 10 Ω resistor is
0.27 A
0.31 A
0.031 A
0.53 A
Correct Answer
Detailed Explanation
Using the loop rule, the total voltage is 7 V - 3 V = 4 V. The total resistance in the circuit is 2 Ω + 1 Ω + 10 Ω = 13 Ω. Therefore, the current I = 4 V / 13 Ω = 0.031 A.
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