STANDARD Physics Galvanometer MCQ Question
If the galvanometer current is 10 mA, resistance of the galvanometer is 40 Ω and shunt of 2 Ω is connected to the galvanometer, the maximum current which can be measured by this ammeter is
0.21 A
2.1 A
210 A
21 A
Correct Answer
Detailed Explanation
The maximum current is calculated using the formula I = (S + G)/S × Ig, where S is the shunt resistance, G is the galvanometer resistance, and Ig is the galvanometer current. Substituting the values, I = (2 + 40)/2 × 0.01 = 0.21 A.
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