STANDARDPhysics-Current Electricity
STANDARD Physics Combination of Resistors MCQ Question
Type: MCQ-numerical-Medium-Class 12
Three resistors of resistances 3 Ω, 4 Ω and 5 Ω are combined in parallel. This combination is connected to a battery of emf 12 V and negligible internal resistance, current through each resistor in ampere is
A
4, 3, 2.4
B
8, 7, 3.4
C
2, 5, 1.8
D
5, 5, 8.2
Correct Answer
Option A
Detailed Explanation
Since the voltage across the circuit is constant, the current through each resistor can be calculated using Ohm's law: I = V/R. For the 3 Ω resistor, I₁ = 12/3 = 4 A. For the 4 Ω resistor, I₂ = 12/4 = 3 A. For the 5 Ω resistor, I₃ = 12/5 = 2.4 A.
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