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STANDARDPhysics-Alternating Current

STANDARD Physics Power in AC Circuits MCQ Question

Type: MCQ-numerical-Medium-Class 12

An inductor of reactance 1 Ω and a resistor of 2 Ω are connected in series to the terminals of a 6 V (rms) ac source. The power dissipated in the circuit is

A

8 W

B

12 W

C

14.4 W

D

18 W

Correct Answer

Option C

Detailed Explanation

Here, Xₗ = 1 Ω, R = 2 Ω, Vₘₛ = 6 V. Impedance of the circuit Z = √(Xₗ² + R²) = √(1² + 2²) = √5 Ω. Iₘₛ = Vₘₛ/Z = 6/√5 A. Power dissipated P = Vₘₛ Iₘₛ cos φ = Vₘₛ Iₘₛ R/Z = 6 × 6/√5 × 2/√5 = 72/5 = 14.4 W.

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