STANDARDPhysics-Alternating Current
STANDARD Physics Power Factor MCQ Question
Type: MCQ-numerical-Medium-Class 12
A resistor of 500 Ω and an inductance of 0.5 H are in series with an ac source which is given by V = 100√2 sin(1000t). The power factor of the combination is
A
1/√2
B
1/√3
C
0.5
D
0.6
Correct Answer
Option A
Detailed Explanation
The impedance Z is calculated using Z = √(R² + (X_L - X_C)²). Here, X_L = ωL = 1000 × 0.5 = 500 Ω. The power factor is cos(ϕ) = R/Z = 500/500√2 = 1/√2.
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